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IWPEC
2009
Springer

Planar Capacitated Dominating Set Is W[1]-Hard

14 years 6 months ago
Planar Capacitated Dominating Set Is W[1]-Hard
Given a graph G together with a capacity function c : V (G) → N, we call S ⊆ V (G) a capacitated dominating set if there exists a mapping f : (V (G) \ S) → S which maps every vertex in (V (G) \ S) to one of its neighbors such that the total number of vertices mapped by f to any vertex v ∈ S does not exceed c(v). In the Planar Capacitated Dominating Set problem we are given a planar graph G, a capacity function c and a positive integer k and asked whether G has a capacitated dominating set of size at most k. In this paper we show that Planar Capacitated Dominating Set is W [1]-hard, resolving an open problem of Dom et al. [IWPEC, 2008 ]. This is the first bidimensional problem to be shown W [1]-hard. Thus Planar Capacitated Dominating Set can become a useful starting point for reductions showing parameterized intractablility of planar graph problems.
Hans L. Bodlaender, Daniel Lokshtanov, Eelko Penni
Added 27 May 2010
Updated 27 May 2010
Type Conference
Year 2009
Where IWPEC
Authors Hans L. Bodlaender, Daniel Lokshtanov, Eelko Penninkx
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