A solution to a problem of Erdos, Rubin and Taylor is obtained by showing that if a graph G is (a : b)-choosable, and c/d > a/b, then G is not necessarily (c : d)-choosable. The simplest case of another problem, stated by the same authors, is settled, proving that every 2-choosable graph is also (4 : 2)-choosable. Applying probabilistic methods, an upper bound for the kth choice number of a graph is given. We also prove that a directed graph with maximum outdegree d